Given the line 2x - 3y - 5 = 0, how do you find the slope of a line that is perpendicular to this line?

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Answer 1 · 2018-06-15T07:34:46

#-3/2#

#2x-3y-5=0#

first rearrange to the form

#y=mx+c#

#2x-5=3y#

#:. y=2/3x-5/3#

now #m=" the slope/grdient"#

#=> m=2/3#

for teh perpendicular slope we use teh relation

#m_1m_2=-1#

#:.m_2=-1/m_1=-1/(2/3)=-3/2#