How do you multiply #(3n ^ { 2} ) ^ { 3} \cdot 2n ^ { 2}#?

1 Answer
Dani
Jun 16, 2018

The answer is #54n^8#

Explanation:

Firstly expand the brackets: #(3n^2)^3# = #3^3*n^(2*3)#

Then collect the coefficients and variables:

= #3^3*n^(2*3)*2n^2#
= #27*2*n^(2*3)*n^2#

Lastly, multiply the coefficients and add the powers:

= #54*n^(6+2)#
= #54 n^8#

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