How do you simplify #(4x ^ { 2} + 19x + 17) \div ( x + 4)#?

1 Answer
Barney V.
Jun 16, 2018

#4x+3+5/(x+4)#

Explanation:

#color(white)(.........)color(white)(..)4x+3#
#x+4|overline(4x^2+19x+17)#
#color(white)(............)ul(4x^2+16x)#
#color(white)(......................)3x+17#
#color(white)(......................)ul(3x+12)#
#color(white)(.................................)5#

#(4x^2+19x+17) / (x+4) = 4x+3+5/(x+4)#

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