How do you graph #r=2+2costheta#?

1 Answer
Jun 18, 2018

Take a sample point and draw.

Explanation:

get a sample point of #0, pi/6, pi/3, pi/2, pi#(or more)
draw a curve connecting each line.
Since there are only function of #costheta# related to angle #theta#,
the graph is symmetry to polar axis.
graph{((x^2)+(y^2))^2=4(x^3+y^2+x*(y^2)) [-10, 10, -5, 5]}
These type of graph is called Limaçon.
general form is #r=a+b cos theta#
The shape depends on the relationship between a and b.
In this case a=b