Question

What is the derivative of `y=sin(tan2x)`?

Answer 1

`2sec^2 2xcostan2x`

Explanation:

Use the chain rule:
`d/dx[sintan2x]=costan2x*d/dx[tan2x]`
`=costan2x*sec^2 2x*d/dx[2x]`
`=2sec^2 2xcostan2x`