A body of mass 10kg moving with a constant velocity of 10m/s.when a constant force acts for 4sec on it .it moves with velocity 2m/s in opposite direction the acceleration produced is ?

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Answer 1 · 2018-06-19T16:12:48

$a = (Deltav)/(Deltat)$

I shall assign a negative sign to the final velocity:

$v_2 = -2" m/s"$

And a positive sign to the initial velocity:

$v_1 = 10" m/s"$

$Deltav = v_2 - v_1$

$Deltav = -2" m/s" - 10" m/s"$

$Deltav = -12" m/s"$

We are given $Deltat = 4" s"$

$a = (-12" m/s")/(4" s")$

$a = -3" m/s"^2$