What is the distance between P(-3, -2) and Q(11, 0)?

1 Answer
Jun 20, 2018

d = 10sqrt2d=102

Explanation:

The distance formula for two points (x_1,y_1)(x1,y1) and (x_2,y_2)(x2,y2) is:

d = sqrt((x_2-x_1)^2+(y_2-y_1)^2)d=(x2x1)2+(y2y1)2

Substituting in the points (-3,-2)(3,2) and (11,0)(11,0):

d = sqrt((11--3)^2+(0--2)^2)d=(113)2+(02)2

d = sqrt(14^2+2^2)d=142+22

d = sqrt(196+4)d=196+4

d = sqrt(200)d=200

d = 10sqrt2d=102