What is the distance between P(-3, -2) and Q(11, 0)?

Question

1265 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-20T16:29:47

$d = 10 \sqrt{2}$ $d = 10sqrt2$

The distance formula for two points $(x_{1}, y_{1})$ $(x_1,y_1)$ and $(x_{2}, y_{2})$ $(x_2,y_2)$ is:

$d = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2}}$ $d = sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

Substituting in the points $(- 3, - 2)$ $(-3,-2)$ and $(11, 0)$ $(11,0)$ :

$d = \sqrt{{(11 - - 3)}^{2} + {(0 - - 2)}^{2}}$ $d = sqrt((11--3)^2+(0--2)^2)$

$d = \sqrt{14^{2} + 2^{2}}$ $d = sqrt(14^2+2^2)$

$d = \sqrt{196 + 4}$ $d = sqrt(196+4)$

$d = \sqrt{200}$ $d = sqrt(200)$

$d = 10 \sqrt{2}$ $d = 10sqrt2$