Find the perimeter of the triangle with vertices (−2,2), (0,4), and (1,−2)?

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Answer 1 · 2018-06-22T15:53:17

Perimeter $= 6.08 + 5 + 2.83 = 13.91$ $color(green)(= 6.08 + 5 + 2.83 = 13.91$

$A (- 2, 2), B (0, 4), C (1, - 2)$ $A(-2,2), B(0,4), C(1,-2)$

$a = \sqrt{{(0 - 1)}^{2} + {(4 + 2)}^{2}} = 6.08$ $a = sqrt((0-1)^2+(4+2)^2) = 6.08$

$b = \sqrt{{(1 + 2)}^{2} + {(- 2 - 2)}^{2}} = 5$ $b = sqrt((1+2)^2+(-2-2)^2) = 5$

$c = \sqrt{{(- 2 - 0)}^{2} + {(2 - 4)}^{2}} = 2.83$ $c = sqrt((-2-0)^2+(2-4)^2) = 2.83$

Perimeter $= 6.08 + 5 + 2.83 = 13.91$ $color(green)(= 6.08 + 5 + 2.83 = 13.91$

Answer 2 · 2018-06-22T15:56:31

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