A object starts from rest and after 30 seconds it reaches to a velocity of 40m/s. Find the distance covered in this time?

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Answer 1 · 2018-06-25T08:23:50

$600 m$ $600m$

we have

$u = 0 m s^{- 1}$ $u=0ms^(-1)$

$v = 40 m s^{- 1}$ $v=40ms^(-1)$

$t = 30 s$ $t=30s$

we want the distance $s$ $s$

find the acceleration first

$v = u + a t$ $v=u+at$

$\Rightarrow a = \frac{v - u}{t} = \frac{40 - 0}{30}$ $=>a=(v-u)/t=(40-0)/30$

$a = \frac{4}{3} m s^{- 2}$ $a=4/3ms^-2$

$v^{2} = u^{2} + 2 a s$ $v^2=u^2+2as$

$40^{2} = 0 + 2 \times (\frac{4}{3}) \times s$ $40^2=0+2xx(4/3)xxs$

$:.s=(3xxcancel(1600)^200)/cancel(8)^1$

$s=600m$