A object starts from rest and after 30 seconds it reaches to a velocity of 40m/s. Find the distance covered in this time?

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Answer 1 · 2018-06-25T08:23:50

#600m#

we have

#u=0ms^(-1)#

#v=40ms^(-1)#

#t=30s#

we want the distance #s#

find the acceleration first

#v=u+at#

#=>a=(v-u)/t=(40-0)/30#

#a=4/3ms^-2#

#v^2=u^2+2as#

#40^2=0+2xx(4/3)xxs#

#:.s=(3xxcancel(1600)^200)/cancel(8)^1#

#s=600m#