Find Cartesian form of equation r=9cos (theta)?
2 Answers
Jun 26, 2018
Explanation:
we need the rectangular
we have
multiply by
using the transformations above
Jun 26, 2018
Explanation:
to convert from polar to cartesian
∙xr=√x2+y2
∙xx=rcosθ⇒cosθ=xr
r=9xr
multiply through by r
r2=9x
x2+y2=9x
x2−9x+y2=0
(x−92)2+y2=814
which is the equation of a circle
centre =(92,0), radius =92