How do you factor $x^{2} + 17 x + 42 = 0$ $x^2 + 17x + 42 =0$ ?

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How do you factor $x^{2} + 17 x + 42 = 0$ $x^2 + 17x + 42 =0$ ?

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Answer 1 · 2018-06-26T08:58:49

-3, -14

Explanation:

$x^{2} + 17 x + 42 = 0$ $x^2 + 17x +42 = 0$
or, $x^{2} + 14 x + 3 x + 42 = 0$ $x^2 + 14x + 3x +42 = 0$
or, $x (x + 14) + 3 (x + 14) = 0$ $x(x + 14) + 3 (x + 14) = 0$
or, $(x + 3) (x + 14)$ $(x + 3)(x+14)$ = 0
or, $x = - 3, - 14$ $x= -3, -14$

Answer 2 · 2018-06-26T09:14:46

$(x + 3) (x + 14) = 0$ $(x+3)(x+14)=0$

Explanation:

$the factors of + 42 which sum to + 17$ $"the factors of " +42" which sum to "+17$
$are + 3 and + 14$ $"are "+3" and "+14$

$x^{2} + 17 x + 42 = 0$ $x^2+17x+42=0$

$(x + 3) (x + 14) = 0$ $(x+3)(x+14)=0$

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How do you factor $x^{2} + 17 x + 42 = 0$ $x^2 + 17x + 42 =0$ ?

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Science

Math

Humanities

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How do you factor x2+17x+42=0x^2 + 17x + 42 =0?

2 Answers

Explanation:

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How do you factor $x^{2} + 17 x + 42 = 0$ $x^2 + 17x + 42 =0$ ?