How do you simplify \frac{-m^{-2}n^{-4}}{(2m^{-2}n^{4}p^{-3})^{0}\cdot 2m^{2}n^{-4}p^{-1}}m2n4(2m2n4p3)02m2n4p1?

1 Answer
Jul 1, 2018

see a solution process below:

Explanation:

First, use this rule of exponents to simplify the denominator of the fraction:

a^color(red)(0) = 1a0=1

(-m^-2n^-4)/((2m^-2n^4p^-3)^color(red)(0) * 2m^2n^-4p^-1) =>m2n4(2m2n4p3)02m2n4p1

(-m^-2n^-4)/(1 * 2m^2n^-4p^-1) =>m2n412m2n4p1

(-m^-2n^-4)/(2m^2n^-4p^-1)m2n42m2n4p1

Next, rewrite the expression as:

(-1m^-2n^-4)/(2m^2n^-4p^-1) =>1m2n42m2n4p1

-1/2(m^-2/m^2)(n^-4/n^-4)(1/p^-1) =>12(m2m2)(n4n4)(1p1)

-1/2(m^-2/m^2)(color(red)(cancel(color(black)(n^-4)))/color(red)(cancel(color(black)(n^-4))))(1/p^-1) =>

-1/2(m^-2/m^2) * 1 * (1/p^-1) =>

-1/2(m^-2/m^2)(1/p^-1)

Next, use this rule for exponents to simplify the m terms:

x^color(red)(a)/x^color(blue)(b) = 1/x^(color(blue)(b)-color(red)(a))

-1/2(m^color(red)(-2)/m^color(blue)(2))(1/p^-1) =>

-1/2(1/m^(color(blue)(2)-color(red)(-2)))(1/p^-1) =>

-1/2(1/m^(color(blue)(2)+color(red)(2)))(1/p^-1) =>

-1/2(1/m^4)(1/p^-1) =>

-1/(2m^4)(1/p^-1)

Now, use these rules for exponents to simplify the p term:

1/x^color(red)(a) = x^color(red)(-a) and a^color(red)(1) = a

-1/(2m^4)(1/p^color(red)(-1)) =>

-1/(2m^4)(p^color(red)(- -1)) =>

-1/(2m^4)(p^color(red)(1)) =>

-1/(2m^4)(p) =>

-p/(2m^4)