Question

How do you solve the right triangle if the hypotenuse is 12 cm long and opposite to that is x and in between the two sides is an angle of 28 degrees?

Answer 1

Use `cos theta = (adj)/(hyp)`

`cos 28=x/12`

`x=12cos28`

`x~~10.6`

The third angle would be `62^@`

`cos 62=(adj)/12`

`adj=12cos62`

`adj~~5.6`