A ship is anchored off a long straight shoreline that runs north and south. From two observation points 15 mi apart on shore, the bearings of the ship are N 31 degrees E and S 53 degrees E. What is the shortest distance from the ship to the shore?

1 Answer
Jul 13, 2018

color(magenta)(6.2 "miles to the nearest 1 decimal place"

Explanation:

:."Let the triangle with the ship and shorline be ABC and let the shortest distance be AD"

:.angle ADC and angle ADB=90^@

:.In triangle ABD angle "BAD"= 180^@-(90^@+31^@)=59^@

:.In triangle ACD angle "CAD"= 180^@-(90^@+53^@)=37^@

:.angle BAC=59^@+37^@=96^@

Sine rule

:.(AB)/sinC=(BC)/sinA

:.AB=(BC*sinC)/sin A

:.AB=(15*sin 53)/sin 96^@

:.AB=12.046mi

:.AD=sin31^@*12.046

:.color(magenta)(=6.204mi="shortest distance"

check:-

:.(AC)/sinB=(AB)/sinC

:.(AC)/(sin31^@)=(12.046*sin31)/sin53^@

:.AC=7.768mi

:.color(magenta)(AD=cos37^@*7.768=6.204mi