Which term of the geometric sequence 2, 6, 18, ... is 118098?

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Answer 1 · 2018-07-19T03:38:02

11th term

Common ratio $r$ is $3$

and first term is $2$

Therefore:
$a_n=2(3)^(n-1)$

$118098= 2(3)^(n-1)$

$59049=3^(n-1)$

$log_3(59049)+1=n$

$10+1=n$

$n=11$