How do you solve $e^{6 x - 7} - 5 = 28, 602$ $e^ { 6x - 7} - 5= 28,602$ ?

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Answer 1 · 2018-07-19T23:55:45

$x = \frac{ln (28607) + 7}{6}$ $x=( ln(28607)+7)/6$

$e^{6 x - 7} - 5 = 28, 602$ $e^ { 6x - 7} - 5= 28,602$

$e^{6 x - 7} = 28, 607$ $e^ { 6x - 7} = 28,607$

$ln 28607 = 6 x - 7$ $ln28607=6x-7$

$x = \frac{ln (28607) + 7}{6}$ $x=( ln(28607)+7)/6$

How do you solve e6x−7−5=28,602e^ { 6x - 7} - 5= 28,602?