How do you solve $\frac{x}{3} - \frac{y}{7} = - 1$ $\frac { x } { 3} - \frac { y } { 7} = - 1$ ?

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Answer 1 · 2018-07-20T07:06:57

Multiply by 21

$7 x - 3 y = - 21$ $7x-3y=-21$

Add 3y

$7 x = 3 y - 21$ $7x=3y-21$

Divide by 7

$x = \frac{3}{7} y - 3$ $x=3/7y-3$

OR

$7 x = 3 y - 21$ $7x=3y-21$

Add 21

$7 x + 21 = 3 y$ $7x+21=3y$

Divide by 3

$\frac{7}{3} x + 7 = y$ $7/3x+7=y$

How do you solve \frac { x } { 3} - \frac { y } { 7} = - 1x3−y7=−1\frac { x } { 3} - \frac { y } { 7} = - 1?