If a heater with power 1000 W gives $3.6*10^6$ heat energy in 1 hour. What will be the temperature raised in 50kg of water with temperature $30^@$ C by that heat?

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Answer 1 · 2018-07-23T21:16:51

$t_f=47.2^@C$

Let's say I didn't know the units on $3.6*10^6$ , I can prove that the units have to be $J$

A watt is a $J/s$

$(1000J)/s*(3600s)/(1hr)= 3.6*10^6 J/(hr)$

$q=mcDeltat$

$3.6*10^6 J= 50,000g*4.184 J/(g^@C)*(t_f-30^@C)$

$3.6*10^6 J= 209,200 J/(C)t_f-6.276*10^6J$

$(9.876*10^6J)/(209200J/C)= t_f$

$t_f=47.2^@C$

If a heater with power 1000 W gives 3.6*10^63.6*10^6 heat energy in 1 hour. What will be the temperature raised in 50kg of water with temperature 30^@30^@C by that heat?