What is the standard form of y=(2x+7)(-3x-3) -4x^2-8x?

2 Answers
Jul 26, 2018

y=-10x^2-35x-21

Explanation:

Given -

y=(2x+7)(-3x-3)-4x^2-8x

y=-6x^2-21x-6x-21-4x^2-8x

y=-10x^2-35x-21

Jul 26, 2018

Expand the brackets

y=(2x+7)(-3x-3)-4x^2-8x

=> y=-6x^2-6x-21x-21-4x^2-8x

Collect like terms

=> y=-10x^2-35x-21

Now it is in the form y=ax^2+bx+c