How do you find the inverse of #f(x)= absx + 1#?

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Answer 1 · 2018-07-26T18:41:38

# f^-1" does not exist"#.

Note that, for the function #f# defined by #f(x)=|x|+1,#

#f(-1)=|-1|+1=1+1=2, and #

#f(1)=|1|+1=2#.

So, #f(-1)=f(1)#.

Therefore, #f# is not #1-1#.

We know that #f^-1" exists "iff f" is 1-1 and onto"#.

Hence, for the given function #f#, its inverse does not exist.