What is the length of the major axis of the conic section $\frac{{(x + 2)}^{2}}{49} + \frac{{(y - 1)}^{2}}{25} = 1$ $(x+2)^2/49 + (y-1)^2/25 =1$ ?

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Answer 1 · 2018-07-27T04:41:21

$14$ $14$ .

If the eqn. of an ellipse is $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1, a > b,$ $x^2/a^2+y^2/b^2=1, a gt b,$

the length of its major axis is $2 a$ $2a$ .

In our case, $a^2=49, b^2=25. :. a=7, b=5, and, a gt b.$

Hence, the required length is $2xx7=14$ .

What is the length of the major axis of the conic section (x+2)^2/49 + (y-1)^2/25 =1(x+2)249+(y−1)225=1(x+2)^2/49 + (y-1)^2/25 =1?