How do you write a polynomial function in standard form with zeros at -6, 2, and 5?

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Answer 1 · 2018-08-02T08:45:16

$x^3-x^2-32x+60$

If $alpha,beta$ and $gamma$ are the zeros,

the polynomial function is $(x-alpha)(x-beta)(x-gamma)$

Hence, for zeros $-6,2$ and $5$ polynomial function is

$(x-(-6))(x-2)(x-5)$

= $(x+6)(x^2-5x-2x+10)$

= $(x+6)(x^2-7x+10)$

= $x^3-7x^2+10x+6x^2-42x+60$

= $x^3-x^2-32x+60$