Question

How do you write the equation for a circle with (5, -2) and radius of 6?

Answer 1

the general equation is `(x-a)^2+(y-b)^2=r^2`

Where `(a,b)` is the centre and `r` is the radius.

So (5,-2) and radius 6 gives

`(x-5)^2+(y+2)^2=36`