What is $12x-4y=-8$ written in slope-intercept form?

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Answer 1 · 2018-08-03T13:52:10

See a solution process below:

The slope-intercept form of a linear equation is: $y = color(red)(m)x + color(blue)(b)$

Where $color(red)(m)$ is the slope and $color(blue)(b)$ is the y-intercept value.

Solving this equation for $y$ gives:

$12x - 4y = -8$

$-color(red)(12x) + 12x - 4y = -color(red)(12x) - 8$

$0 - 4y = -12x - 8$

$-4y = -12x - 8$

$(-4y)/color(red)(-4) = (-12x - 8)/color(red)(-4)$

$(color(red)(cancel(color(black)(-4)))y)/cancel(color(red)(-4)) = (-12x)/color(red)(-4) - 8/color(red)(-4)$

$y = 3x - (-2)$

$y = color(red)(3)x + color(blue)(2)$

Answer 2 · 2018-08-03T14:12:51

$color(crimson)(y = 3 x + 2$

Slope = m = 3, y-intercept = c = 2#

Slope- intercept form of equation $y = m x + c$

$12x - 4y = -8$

$12x + 8 = 4y$

$y = (12/4)x + (8/2)$

$color(crimson)(y = 3 x + 2$

Slope = m = 3, y-intercept = c = 2#

What is 12x-4y=-812x-4y=-8 written in slope-intercept form?