Question

How do you factor the trinomial `8x^2 − 11x + 3`?

Answer 1

`8x^2-11x+3=(x-1)(8x-3)`

Explanation:

`8x^2-11x+3`

`=8x^2-8x-3x+3`

`=8x(x-1)-3(x-1)`

`=(x-1)(8x-3)`

Answer 2

`(x-1)(8x-3)`

Explanation:

`"factor the quadratic using the a-c method"`

`"the factors of "8xx3=24`

`"which sum to "-11" are "-8" and "-3`

`"use these factors to split the middle term"`

`8x^2-8x-3x+3larrcolor(blue)"factor by grouping"`

`=color(red)(8x)(x-1)color(red)(-3)(x-1)`

`"take out the "color(blue)"common factor "(x-1)`

`=(x-1)(color(red)(8x-3))`

`8x^2-11x+3=(x-1)(8x-3)`