What will be the answer?

. A train is moving forward at a velocity of 2.0 m/s. At the instant the train begins to accelerate at 0.80 m/s2, a passenger drops a quarter which takes 0.50 s to fall to the floor. Relative to a spot on the floor directly under the quarter at release, it lands:
(A) 1.1 m toward the rear of the train.
(B) 1.0 m toward the rear of the train.
(C) 0.10 m toward the rear of the train.
(D) directly on the spot.
(E) 0.90 m toward the front of the train.

1 Answer
Aug 4, 2018

Option C is the answer

Explanation:

Due to inertia of motion the quarter at the time of its release will have same velocity as that of the train i.e.2m/s. As the time of fall is 0.5s it will move 2×0.5=1m towards the front of the train during its time of flight.

But the train will move with acceleration 0.8ms2 and will move during the time of fall of the quarter by the distance =2×0.5+12×0.8×(0.5)2=1.1 m
Hence the quarter will fall 0.1m toward the rear of the train relative to the spot directly under the quarter at release.

Option C is the answer