How do you find the amplitude, period, and shift for y = 3 sin(3x- π)?

1 Answer
Aug 5, 2018

3,(2pi)/3,pi/3

Explanation:

"the standard form of the sine function is"

color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))

"amplitude "=|a|," period "=(2pi)/b

"phase shift "=-c/b," vertical shift "=d

"here "a=3,b=3,c=-pi,d=0

"amplitude "=|3|=3," period "=(2pi)/3

"phase shift "=-(-pi)/3=pi/3