How do you factor $t^{4} - t^{2}$ $t^4-t^2$ completely?

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How do you factor $t^{4} - t^{2}$ $t^4-t^2$ completely?

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Answer 1 · 2018-08-06T15:33:24

$t^{2} (t - 1) (t + 1)$ $t^2(t-1)(t+1)$

Explanation:

$take out a common factor t^{2}$ $"take out a "color(blue)"common factor "t^2$

$= t^{2} (t^{2} - 1)$ $=t^2(t^2-1)$

$t^{2} - 1 is a difference of squares$ $t^2-1color(blue)" is a difference of squares"$

$= t^{2} (t - 1) (t + 1)$ $=t^2(t-1)(t+1)$

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How do you factor $t^{4} - t^{2}$ $t^4-t^2$ completely?

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