Question

A right triangle has a 17 degree angle which is across from a side that is 9cm long. what is the perimeter of this triangle?

Answer 1

The 9 cm would be the base of the triangle, using trig we can find the height (h)

`tan theta= "opp"/"adj"`

`tan 17=9/"h"`

`"h"=9/(tan 17)`

Use Pythagoras to find the hypotenuse

`a^2+b^2=c^2 => 9^2+(9/(tan 17))^2=c^2`

`c^2~~947.576625`

`c=sqrt947.576625`

Perimeter = 9 + h + c

Perimeter `~~ 69.22040614`

P=69.2 cm (1 dp)