How do you write an equation for a circle with center at (3, -6); radius = 5?

1 Answer
Jim G.
Aug 8, 2018

(x-3)^2+(y+6)^2=25(x−3)2+(y+6)2=25

Explanation:

"the equation of a circle in standard form is"the equation of a circle in standard form is

color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))

"where "(a,b)" are the coordinates of the centre and r"
"is the radius"

"here "(a,b)=(3,-6)" and "r=5

(x-3)^2+(y+6)^2=25larrcolor(red)" is equation of circle"

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