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How do you solve $log_2 (x+1) = 0$ ?

1 Answer

Shwetank Mauria

Aug 8, 2018

$x=0$

Explanation:

As $log_2(x+1)=0$ , we have $2^0=x+1$

i.e. $x+1=1$ i.e. $x=0$

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