A force of 3kgf is just sufficient to pull a block of 5kgf .Find the coefficient of friction and angle of Friction?

1 Answer

mu_s=0.6
Yes, the value of phi is wrong.
phi is tan^-1(0.6)= 30.96376
->31 degrees approx

Explanation:

Coefficient of friction mu_sis the ratio of friction force to the normal thrust.
Here, the pulling force need to be little more than the friction force beneath the block.
The limiting static friction shall be 3 kgf.
The normal thrust is due to the weight of the block itself.
The normal reaction shall be 5 kgf.
Thus, coefficient of friction mu_s=3/5=0.6
Angle of friction phiand the coefficient of friction mu_s are related by the expression mu_s=tanphi
Then,
0.6=tanphi
phi=tan^-1 0.6=36.^0 870

mu_s=0.6
phi = 36.^0 870