What is the antiderivative of $m(x) = (-2/y^3)$ ?

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Answer 1 · 2018-08-09T11:53:53

$M(x)=-2/y^3x+C$ , $C in RR$

you have $m(x)=-2/y^3$ , because m depends of x, you consider $-2/y^3$ as a constant.

So:

$M(x)=intm(x)dx=int-2/y^3dx=-2/y^3x+C$ , $C in RR$

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What is the antiderivative of m(x) = (-2/y^3)m(x) = (-2/y^3)?