What is an equation in slope-intercept form for the line through point P(-5,2) and perpendicular to the line containing the two points (2,3) and (1,-2)?

1 Answer
Aug 13, 2018

y=-1/5x+1y=15x+1

Explanation:

"calculate the slope m using the "color(blue)"gradient formula"calculate the slope m using the gradient formula

•color(white)(x)m=(y_2-y_1)/(x_2-x_1)xm=y2y1x2x1

"let "(x_1,y_1)=(2,3)" and "(x_2,y_2)=(1,-2)let (x1,y1)=(2,3) and (x2,y2)=(1,2)

m=(-2-3)/(1-2)=(-5)/(-1)=5m=2312=51=5

"given a line with slope m then the slope of a line"given a line with slope m then the slope of a line
"perpendicular to it is"perpendicular to it is

•color(white)(x)m_(color(red)"perpendicular")=-1/mxmperpendicular=1m

m_("perpendicular")=-1/5mperpendicular=15

"the equation of a line in "color(blue)"slope-intercept form"the equation of a line in slope-intercept form is.

•color(white)(x)y=mx+cxy=mx+c

"where m is the slope and c the y-intercept"where m is the slope and c the y-intercept

y=-1/5x+clarrcolor(blue)"is the partial equation"y=15x+cis the partial equation

"to find c substitute "(-5,2)" into the partial equation"to find c substitute (5,2) into the partial equation

2=1+crArrc=2-1=12=1+cc=21=1

y=-1/5x+1larrcolor(red)"equation of perpendicular line"y=15x+1equation of perpendicular line