What is $\frac{3}{64} + \frac{1}{8}$ $3/64 +1/8$ ???

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What is $\frac{3}{64} + \frac{1}{8}$ $3/64 +1/8$ ???

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Answer 1 · 2018-08-14T14:12:13

$\frac{11}{64}$ $11/64$

Explanation:

$we require the fractions to have a common denominator$ $"we require the fractions to have a "color(blue)"common denominator"$

$multiply the numerator/denominator of \frac{1}{8} by 8$ $"multiply the numerator/denominator of "1/8" by 8"$

$\frac{1}{8} \times \frac{8}{8} = \frac{8}{64}$ $1/8xx8/8=8/64$

$we now have \frac{3}{64} + \frac{8}{64} \leftarrow common denominator$ $"we now have "3/64+8/64larrcolor(blue)"common denominator"$

$add the numerators leaving the denominator$ $"add the numerators leaving the denominator"$

$\frac{3}{64} + \frac{8}{64} = \frac{3 + 8}{64} = \frac{11}{64}$ $3/64+8/64=(3+8)/64=11/64$

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What is $\frac{3}{64} + \frac{1}{8}$ $3/64 +1/8$ ???

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