Determining the Volume of a Solid of Revolution
Key Questions
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Let us look at the polar curve
r=3sinθ .The above is actually equivalent to the circle with radius
32 , centered at(0,32) , whose equation is:x2+(y−32)2=(32)2 by solving for
y , we havey=±√(32)2−x2+32 By Washer Method, the volume of the solid of revolution can be found by
V=π∫32−32⎡⎢⎣⎛⎝√(32)2−x2+32⎞⎠2−⎛⎝−√(32)2−x2+32⎞⎠2⎤⎥⎦dx by simplifying the integrand,
=6π∫32−32√(32)2−x2dx since the integral can be interpreted as the area of semicircle with radus
32 ,=6π⋅π(32)22=27π24
I hope that this was helpful.
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