Determining the Volume of a Solid of Revolution

Key Questions

  • Let us look at the polar curve r=3sinθ.

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    The above is actually equivalent to the circle with radius 32, centered at (0,32), whose equation is:

    x2+(y32)2=(32)2

    by solving for y, we have

    y=±(32)2x2+32

    By Washer Method, the volume of the solid of revolution can be found by

    V=π3232(32)2x2+322(32)2x2+322dx

    by simplifying the integrand,

    =6π3232(32)2x2dx

    since the integral can be interpreted as the area of semicircle with radus 32,

    =6ππ(32)22=27π24


    I hope that this was helpful.

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