2NO(g) + O2 (g) --> 2NO2 How many moles of O2 are required to produce 92.0 g NO2?

2NO(g) + O_2 (g) -> 2NO_22NO(g)+O2(g)2NO2

1 Answer
Apr 28, 2018

2NO(g) + O_2 (g) -> 2NO_2(g)2NO(g)+O2(g)2NO2(g)

This equation tells us that for every 22 moles of NO_2NO2 formed ; we require 11 mole of O_2O2.

Explanation:

So given amount of NO_2 NO2 formed = 92g=92g

Molar mass of NO_2 = (14+16xx2)g=46gNO2=(14+16×2)g=46g

So number of moles of NO_2NO2 formed =92/46=2=9246=2moles

:. The mole of O_2 required here =1 mole