#30 xx 1.1 + 20 xx (1.1 - x/2) = 40 xx (x - 1.1).# How to solve for #x#?

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Answer 1 · 2017-04-21T20:13:14

#x = 1.386#

#color(red)(30 xx 1.1) +color(blue)(20xx(1.1-x/2)) = color(green)(40 xx (x-1.1))#

First, multiply into the brackets to get rid of them,

#color(red)(3.3) +color(blue)(22-10x) = color(green)(40x-44)" "larr# simplify

#25.3 -10x = 40x-44" "larr# isolate the #x#-terms

#25.3+44 =40x+10x#

]#69.3 = 50x" "larr div 50# on both sides

#69.3/50 = (50x)/50#

#1.386 = x#