$34^{2} + 25^{2} + 86^{2} =$ $34^2+25^2+86^2=$ ?

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Answer 1 · 2016-01-06T13:13:24

$9177$ $9177$

$34^{2} = 34 \cdot 34 = 1156$ $34^2=34*34=1156$

$25^{2} = 25 \cdot 25 = 625$ $25^2=25*25=625$

$86^{2} = 86 \cdot 86 = 7396$ $86^2=86*86=7396$

$S o, 1156 + 625 + 7396 = 9177$ $So,1156+625+7396=9177$

342+252+862=34^2+25^2+86^2=?