4.65 L of nitrogen at standard pressure is compressed into a 0.480 L container. What is the new pressure in mm Hg?

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Answer 1 · 2018-05-07T20:03:47

#P_2# = 7362.5 mmHg

Boyle's Law
#P_1##V_1# = #P_2##V_2#

(760mmHg)(4.65L) = #P_2#(0.480L)

Divide (760mmHg * 4.65L) by (0.480L) to isolate for #P_2#.

#(760 * 4.65)/(0.480) = #P_2#

Simplify.

#(3534/0.480)# = #P_2#

7362.5 mmHg = #P_2#