Question

40g of NaOH is added to water to create 1 L of solution. The resulting solution has a SG of 1.07. a) Calculate the mass (in lb) of 1 L of solution? b) Calculate the molecular mass of NaOH? c) Calculate the molarity of NaOH in the solution.?

Answer 1

We know that the density of the solution, `rho_"solution"=1.07*g*mL^-1`

Explanation:

`a.` And so if we gots a `1*L` volume....then we have a mass of.....

`1000*mLxx1.07*g*mL^-1=1070*g`..

But `1*lb-=454*g`...

And so `1070*g-=1070*gxx1/(454*g*lb^-1)=2.36*1/(lb^-1)` `=2.36*1/(1/(lb))=2.36*lb`

`b.` And the molar mass of `NaOH` is simply....

`(22.99+15.999+1.00794)*g*mol^-1=40.0*g*mol^-1`.

`c.` And the molarity is simply the quotient....

`"Molarity"="Moles of solute"/"Volume of solution"`

`=((40*g)/(40.0*g*mol^-1))/(1.00*L)=1.00*mol*L^-1`.....

I don't know why the septic tanks don't go back to using pounds, shillings, and pence if they are bent upon using `"lbs"`, and `"inches"`, and `"tons"`. And while they are at it, they could recognize Queen Elizabeth II as their lawful sovereign.