$48^{2} + 52^{2} + 63^{2} =$ $48^2+52^2+63^2=$ ?

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Answer 1 · 2016-01-03T04:22:53

$8977$ $8977$

$\to$ $rarr$ $48^{2} = 48 \cdot 48 = 2304$ $48^2=48*48=2304$

$\to$ $rarr$ $52^{2} = 52 \cdot 52 = 2704$ $52^2=52*52=2704$

$\to$ $rarr$ $63^{2} = 63 \cdot 63 = 3969$ $63^2=63*63=3969$

$S o$ $So$ $...2304+2704+3969=8977$

48^2+52^2+63^2=482+522+632=48^2+52^2+63^2=?