Question

Question #f8fc7

Answer 1

See below.

Explanation:

This depends on whether the pipe is closed or open-ended.

The fundamental frequency of a pipe is the simplest, smallest portion of a wave that can fit into a pipe. At the open end of a pipe, there is always an antinode - an area with maximum air movement.

If it is an open-ended pipe, there is an antinode at each end, meaning that the length of the pipe is equal to `L = 1/2 lambda`.

Manipulating the formula `v = f lambda` to solve for the fundamental frequency leaves us with

`f = v / (2L) ->` in an open-ended pipe.

https://www.okphysics.com/4-44-fundamental-frequency-of-open-and-closed-pipe/

If it is a closed-ended pipe, there is an antinode at the open end and a node at the closed end - causing the sound to reflect - meaning that the length of the pipe is equal to `L = 1/4 lambda`.

Again, if we manipulate the formula `v = f lambda` to solve for the fundamental frequency, this leaves us with

`f = v / (4L) ->` in a closed-ended pipe.

https://www.okphysics.com/4-44-fundamental-frequency-of-open-and-closed-pipe/

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