Question

Question #c9cea

Answer 1

Well, the volume of the quartz will be equal to the difference between water levels before and after you've placed it in the cylinder.

So, you start with `"25 mL"` and add the quartz. You see that the water level increased to `"36.50 mL"`. This increase can only represent an added volume, which, in this case, is equal to

`V_("added") = "36.50 mL" - "25 mL" = "11.5 mL"`

That is the volume of the stone quartz. Since you know how much it weighs, you can automatically determine its density

`rho = m/V = ("30.475 g")/("11.5 mL") = "2.65 g/mL"`

This method is used to determine an object's volume by water displacement.

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