Question #6e9f3

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Answer 1 · 2015-08-30T16:35:52

$V = 3.31 \cdot 10^{- 29} m^{3}$ $V = 3.31 * 10^(-29)"m"""^3$

All you really need to do here is plug the value of $r$ $r$ in the formula for the volume of the sphere and solve for $V$ $V$ .

Before doing that, convert the radius from picometers to meters

$199color(red)(cancel(color(black)("pm"))) * "1 m"/(10^12color(red)(cancel(color(black)("pm")))) = 199 * 10^(-12)"m"$

The volume of the sphere - expressed in cubic meters - will be

$V = 4/3 * pi * r^3$

$V = 4/3 * pi * (199 * 10^(-12)"m")""^3$

$V = 4/3 * pi * 7,880,599 * 10^(-36)"m"""^3$

$V = 33,101,176 * 10^(-36)"m"""^3$

Round this off to three sig figs, the number of sig figs you gave for the radius of the sphere, to get

$V = color(green)(3.31 * 10^(-29)"m"""^3)$