Question #23caa

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Question #23caa

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Answer 1 · 2015-09-21T03:24:20

0.015 km/s
0.0008 J/kg^-1
5 m/s
-
8 g/cm^3
50 m/s^-2
4200 J/kg

Explanation:

15 m/s to km/s
Note: 1 m = 0.001 km
$15 \frac{m}{s}$ $15 m/s$
$= 15 \frac{0.001 k m}{s}$ $= 15(0.001 km)/s$
$= \frac{0.015 k m}{s}$ $= (0.015km)/s$
Answer: 0.015 km/s

0.8 J/g^-1 to J/kg^-1
Note: 1 g = 0.001 kg
$0.8 \frac{J}{g^{- 1}}$ $0.8 J/g^-1$
$= 0.8 \cdot J \cdot g$ $=0.8*J*g$
$= 0.8 \cdot J \cdot (0.001 k g)$ $=0.8*J*(0.001kg)$
$= 0.0008 \cdot J \cdot k g$ $=0.0008*J*kg$
$= 0.0008 \frac{J}{k g^{- 1}}$ $=0.0008 J/(kg^-1)$
Answer: 0.0008 J/kg^-1

18 km/h to m/s
Note: 1 km = 1000 m; 1 h = 3600 s
$18 \frac{k m}{h}$ $18(km)/h$
$= 18 \frac{1000 m}{3600 s}$ $=18(1000m)/(3600s)$
$= 5 \frac{m}{s}$ $=5m/s$
Answer: 5 m/s

2.5cm^3 to kg/m
Can I get some clarification on the units of this one? I don't think it's convertible.

8000 kg/m^3 to g/cm^3
Note: 1 kg = 1000 g; 1 m = 100 cm
$8000 \frac{k g}{m^{3}}$ $8000 (kg)/m^3$
$= 8000 \frac{1000 g}{{(100 c m)}^{3}}$ $=8000(1000g)/(100cm)^3$
$= 8000 \frac{1000 g}{{(100)}^{3} c m^{3}}$ $=8000(1000g)/((100)^3cm^3$
$= 8 \frac{g}{c m^{3}}$ $=8g/(cm^3)$
Answer: 8 g/cm^3

5000 cm/s^-2 to m/s^-2
Note: 1 cm = 0.01 m
$5000 \frac{c m}{s^{- 2}}$ $5000 (cm)/s^-2$
$= 5000 \frac{0.01 m}{s^{- 2}}$ $=5000(0.01m)/s^-2$
$= 50 \frac{m}{s^{- 2}}$ $=50m/s^-2$
Answer: 50 m/s^-2

4.2 J/g to J/kg
Note: 1 g = 0.001 kg
$4.2 \frac{J}{g}$ $4.2 J/g$
$= 4.2 \frac{J}{0.001 k g}$ $=4.2J/(0.001kg)$
$= 4200 \frac{J}{k g}$ $=4200J/(kg)$
Answer: 4200 J/kg

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Question #23caa

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