$"1351 J"$ of energy are required to heat a $"0.125 kg"$ sample of a metal from $25.0^@"C"$ to $112.1^@"C"$ . What is the specific heat of the metal?

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Answer 1 · 2015-10-27T19:28:09

$124"J/kg·K"$

Heat energy required is given by $W=mcDeltaT$ .

$therefore c= W/(mDeltaT)=(1351"J")/((0,125"kg")(112,1^"o""C"-25.0^"o""C"))="124 J/kg·K"$

"1351 J""1351 J" of energy are required to heat a "0.125 kg""0.125 kg" sample of a metal from 25.0^@"C"25.0^@"C" to 112.1^@"C"112.1^@"C". What is the specific heat of the metal?