Question #6de52

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Question #6de52

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Answer 1 · 2016-03-03T02:27:00

I found $2.8 \frac{g}{c m^{3}}$ $2.8g/(cm^3$

Explanation:

Density is equal to $\frac{mass}{volume}$ $"mass"/"volume"$ so in our case the volume of the stone will be given observing the increase of volume from 3mL to 14 mL immagining that he only contribution to this increase (of 14-3=11mL) is due to the voume of the stone:
so considering $11 m L = 11 c m^{3}$ $11mL=11cm^3$ we have:
Density $= \frac{31}{11} = 2.8 \frac{g}{c m^{3}}$ $=31/11=2.8g/(cm^3)$

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Question #6de52

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