Question #f0003

1 Answer
Feb 11, 2016

You must add 170 cal to melt the iron.

The formula for the heat required is

q = mcΔT

ΔT = "1530 °C – 25 °C" = "1505 °C"

Hence

q= mcΔT = 1.0 color(red)(cancel(color(black)("g"))) × 0.11color(white)(l) "cal"·color(red)(cancel(color(black)("g"^(-1)"°C"^(-1)))) × 1505 color(red)(cancel(color(black)("°C"))) = "170 cal" (2 significant figures)