Question #b1a9b

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Question #b1a9b

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Answer 1 · 2016-03-13T19:00:26

$D = \frac{3000 g}{80, 000 c m^{3}} = .0375 \frac{g}{c m^{3}}$ $D = (3000 g)/(80,000 cm^3) = .0375 g/(cm^3)$

Explanation:

You know density, is given by the ratio of Mass to Volume of the object, $D = \frac{M}{V}$ $D = M/V$ where M = mass and V= Volume
Thus calculate $V = w \times l \times h = 16 \times 100 \times 50 = 80, 000 c m^{3}$ $V= wxxlxxh = 16xx100xx50=80,000 cm^3$
and $D = \frac{3000 g}{80, 000 c m^{3}} = .0375 \frac{g}{c m^{3}}$ $D = (3000 g)/(80,000 cm^3) = .0375 g/(cm^3)$

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